1100101300213 has 4 divisors (see below), whose sum is σ = 1164813141420. Its totient is φ = 1035389459008.

The previous prime is 1100101300159. The next prime is 1100101300217. The reversal of 1100101300213 is 3120031010011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 856007992849 + 244093307364 = 925207^2 + 494058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100101300213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100101300193 and 1100101300202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100101300217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32355920578 + ... + 32355920611.

It is an arithmetic number, because the mean of its divisors is an integer number (291203285355).

Almost surely, 2^{1100101300213} is an apocalyptic number.

It is an amenable number.

1100101300213 is a deficient number, since it is larger than the sum of its proper divisors (64711841207).

1100101300213 is an equidigital number, since it uses as much as digits as its factorization.

1100101300213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64711841206.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1100101300213 its reverse (3120031010011), we get a palindrome (4220132310224).

The spelling of 1100101300213 in words is "one trillion, one hundred billion, one hundred one million, three hundred thousand, two hundred thirteen".