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1100103340431 = 34127413263017
BaseRepresentation
bin10000000000100011010…
…001001101000110001111
310220011120002112000011010
4100000203101031012033
5121011002423343211
62201214104300303
7142323405051414
oct20004321150617
93804502460133
101100103340431
11394607724207
1215925a471693
137c97c31b364
143b3610c810b
151d939ab54a6
hex1002344d18f

1100103340431 has 16 divisors (see below), whose sum is σ = 1503128819808. Its totient is φ = 715253107200.

The previous prime is 1100103340403. The next prime is 1100103340477. The reversal of 1100103340431 is 1340433010011.

It is not a de Polignac number, because 1100103340431 - 221 = 1100101243279 is a prime.

It is a super-2 number, since 2×11001033404312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100103340398 and 1100103340407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100103340331) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1294366 + ... + 1968651.

It is an arithmetic number, because the mean of its divisors is an integer number (93945551238).

Almost surely, 21100103340431 is an apocalyptic number.

1100103340431 is a deficient number, since it is larger than the sum of its proper divisors (403025479377).

1100103340431 is a wasteful number, since it uses less digits than its factorization.

1100103340431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3265802.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1100103340431 its reverse (1340433010011), we get a palindrome (2440536350442).

The spelling of 1100103340431 in words is "one trillion, one hundred billion, one hundred three million, three hundred forty thousand, four hundred thirty-one".

Divisors: 1 3 41 123 2741 8223 112381 337143 3263017 9789051 133783697 401351091 8943929597 26831788791 366701113477 1100103340431