Base | Representation |
---|---|
bin | 10000000000100011010… |
… | …100111101010111000111 |
3 | 10220011120011101000010000 |
4 | 100000203110331113013 |
5 | 121011003201341201 |
6 | 2201214141332343 |
7 | 142323416320521 |
oct | 20004324752707 |
9 | 3804504330100 |
10 | 1100104324551 |
11 | 394608236631 |
12 | 15925a8670b3 |
13 | 7c97c5a428b |
14 | 3b3612a2a11 |
15 | 1d939c0bd86 |
hex | 1002353d5c7 |
1100104324551 has 40 divisors (see below), whose sum is σ = 1658167679520. Its totient is φ = 726825996288.
The previous prime is 1100104324537. The next prime is 1100104324589. The reversal of 1100104324551 is 1554234010011.
1100104324551 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 104 + 3 + 2 + 4 + 551 = 666.
It is not a de Polignac number, because 1100104324551 - 213 = 1100104316359 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100104324511) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3977695 + ... + 4245263.
It is an arithmetic number, because the mean of its divisors is an integer number (41454191988).
Almost surely, 21100104324551 is an apocalyptic number.
1100104324551 is a deficient number, since it is larger than the sum of its proper divisors (558063354969).
1100104324551 is a wasteful number, since it uses less digits than its factorization.
1100104324551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 268037 (or 268028 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 1100104324551 its reverse (1554234010011), we get a palindrome (2654338334562).
The spelling of 1100104324551 in words is "one trillion, one hundred billion, one hundred four million, three hundred twenty-four thousand, five hundred fifty-one".
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