1100110020133 has 4 divisors (see below), whose sum is σ = 1100655441100. Its totient is φ = 1099564599168.

The previous prime is 1100110020089. The next prime is 1100110020181. The reversal of 1100110020133 is 3310200110011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 587027195329 + 513082824804 = 766177^2 + 716298^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100110020133 - 2²⁵ = 1100076465701 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100110029133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272707458 + ... + 272711491.

It is an arithmetic number, because the mean of its divisors is an integer number (275163860275).

Almost surely, 2^{1100110020133} is an apocalyptic number.

It is an amenable number.

1100110020133 is a deficient number, since it is larger than the sum of its proper divisors (545420967).

1100110020133 is an equidigital number, since it uses as much as digits as its factorization.

1100110020133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 545420966.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1100110020133 its reverse (3310200110011), we get a palindrome (4410310130144).

The spelling of 1100110020133 in words is "one trillion, one hundred billion, one hundred ten million, twenty thousand, one hundred thirty-three".