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110011110010983 = 3212473979993319
BaseRepresentation
bin11001000000110111110101…
…001000100011000001100111
3112102111221220101222211001100
4121000313311020203001213
5103404410223130322413
61025550223425531143
732113016601201246
oct3100676510430147
9472457811884040
10110011110010983
11320644a4687955
1210408a821a3ab3
134950006c3615c
141d247cd68a95d
15cab994c82a73
hex640df5223067

110011110010983 has 12 divisors (see below), whose sum is σ = 158917676757840. Its totient is φ = 73334859972576.

The previous prime is 110011110010981. The next prime is 110011110011057. The reversal of 110011110010983 is 389010011110011.

It is not a de Polignac number, because 110011110010983 - 21 = 110011110010981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110011110010981) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 489884403 + ... + 490108916.

It is an arithmetic number, because the mean of its divisors is an integer number (13243139729820).

Almost surely, 2110011110010983 is an apocalyptic number.

110011110010983 is a deficient number, since it is larger than the sum of its proper divisors (48906566746857).

110011110010983 is a wasteful number, since it uses less digits than its factorization.

110011110010983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 980005798 (or 980005795 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 27.

Adding to 110011110010983 its reverse (389010011110011), we get a palindrome (499021121120994).

The spelling of 110011110010983 in words is "one hundred ten trillion, eleven billion, one hundred ten million, ten thousand, nine hundred eighty-three".

Divisors: 1 3 9 12473 37419 112257 979993319 2939979957 8819939871 12223456667887 36670370003661 110011110010983