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11001112301103 = 319319000193957
BaseRepresentation
bin1010000000010110010101…
…1001000000111000101111
31102221200210102122102120120
42200011211121000320233
52420220234222113403
635221501412020023
72213542550451561
oct240054531007057
942850712572516
1011001112301103
113561600106221
12129810a301613
1361a5289c0aa2
142a0657197331
1514126e16ee53
hexa0165640e2f

11001112301103 has 8 divisors (see below), whose sum is σ = 14744150511408. Its totient is φ = 7296074479104.

The previous prime is 11001112301089. The next prime is 11001112301141. The reversal of 11001112301103 is 30110321110011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-11001112301103 is a prime.

It is a super-2 number, since 2×110011123011032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001112306103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9500096400 + ... + 9500097557.

It is an arithmetic number, because the mean of its divisors is an integer number (1843018813926).

Almost surely, 211001112301103 is an apocalyptic number.

11001112301103 is a deficient number, since it is larger than the sum of its proper divisors (3743038210305).

11001112301103 is a wasteful number, since it uses less digits than its factorization.

11001112301103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19000194153.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 11001112301103 its reverse (30110321110011), we get a palindrome (41111433411114).

The spelling of 11001112301103 in words is "eleven trillion, one billion, one hundred twelve million, three hundred one thousand, one hundred three".

Divisors: 1 3 193 579 19000193957 57000581871 3667037433701 11001112301103