Base | Representation |
---|---|
bin | 1010000000010110010111… |
… | …0110011011011101011010 |
3 | 1102221200210222011012002212 |
4 | 2200011211312123131122 |
5 | 2420220243210341442 |
6 | 35221502245155122 |
7 | 2213543003135642 |
oct | 240054566333532 |
9 | 42850728135085 |
10 | 11001120012122 |
11 | 35616044a2669 |
12 | 12981109bbaa2 |
13 | 61a52a490816 |
14 | 2a0658203522 |
15 | 14126eb94a82 |
hex | a0165d9b75a |
11001120012122 has 4 divisors (see below), whose sum is σ = 16501680018186. Its totient is φ = 5500560006060.
The previous prime is 11001120012061. The next prime is 11001120012161. The reversal of 11001120012122 is 22121002110011.
11001120012122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10746850941121 + 254269071001 = 3278239^2 + 504251^2 .
It is a super-2 number, since 2×110011200121222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11001120012097 and 11001120012106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750280003029 + ... + 2750280003032.
Almost surely, 211001120012122 is an apocalyptic number.
11001120012122 is a deficient number, since it is larger than the sum of its proper divisors (5500560006064).
11001120012122 is an equidigital number, since it uses as much as digits as its factorization.
11001120012122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5500560006063.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 11001120012122 its reverse (22121002110011), we get a palindrome (33122122122133).
The spelling of 11001120012122 in words is "eleven trillion, one billion, one hundred twenty million, twelve thousand, one hundred twenty-two".
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