1100112140541 has 4 divisors (see below), whose sum is σ = 1466816187392. Its totient is φ = 733408093692.

The previous prime is 1100112140527. The next prime is 1100112140599. The reversal of 1100112140541 is 1450412110011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1100112140541 - 2¹³ = 1100112132349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100112130541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183352023421 + ... + 183352023426.

It is an arithmetic number, because the mean of its divisors is an integer number (366704046848).

Almost surely, 2^{1100112140541} is an apocalyptic number.

It is an amenable number.

1100112140541 is a deficient number, since it is larger than the sum of its proper divisors (366704046851).

1100112140541 is an equidigital number, since it uses as much as digits as its factorization.

1100112140541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366704046850.

The product of its (nonzero) digits is 160, while the sum is 21.

Adding to 1100112140541 its reverse (1450412110011), we get a palindrome (2550524250552).

The spelling of 1100112140541 in words is "one trillion, one hundred billion, one hundred twelve million, one hundred forty thousand, five hundred forty-one".