Base | Representation |
---|---|
bin | 1010000000010110011001… |
… | …1101111000011001000010 |
3 | 1102221200211200121121211100 |
4 | 2200011212131320121002 |
5 | 2420220303332313432 |
6 | 35221503254555230 |
7 | 2213543160061620 |
oct | 240054635703102 |
9 | 42850750547740 |
10 | 11001130354242 |
11 | 356160a316876 |
12 | 1298114368b16 |
13 | 61a52c672012 |
14 | 2a0659736510 |
15 | 141270a3907c |
hex | a0166778642 |
11001130354242 has 48 divisors (see below), whose sum is σ = 27260620126272. Its totient is φ = 3140904034080.
The previous prime is 11001130354241. The next prime is 11001130354283. The reversal of 11001130354242 is 24245303110011.
11001130354242 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 113 + 0 + 3 + 542 + 4 + 2 = 666.
It is not an unprimeable number, because it can be changed into a prime (11001130354241) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31437348 + ... + 31785359.
It is an arithmetic number, because the mean of its divisors is an integer number (567929585964).
Almost surely, 211001130354242 is an apocalyptic number.
11001130354242 is an abundant number, since it is smaller than the sum of its proper divisors (16259489772030).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11001130354242 is a wasteful number, since it uses less digits than its factorization.
11001130354242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63224103 (or 63224100 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 11001130354242 its reverse (24245303110011), we get a palindrome (35246433464253).
The spelling of 11001130354242 in words is "eleven trillion, one billion, one hundred thirty million, three hundred fifty-four thousand, two hundred forty-two".
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