Base | Representation |
---|---|
bin | 1010000000010110011100… |
… | …0110100000010001001111 |
3 | 1102221200212102122122122111 |
4 | 2200011213012200101033 |
5 | 2420220314044101333 |
6 | 35221504315124451 |
7 | 2213543346433561 |
oct | 240054706402117 |
9 | 42850772578574 |
10 | 11001141003343 |
11 | 356161532a687 |
12 | 1298117a43727 |
13 | 61a53193016a |
14 | 2a065ad09331 |
15 | 14127193e4cd |
hex | a01671a044f |
11001141003343 has 4 divisors (see below), whose sum is σ = 11001220614280. Its totient is φ = 11001061392408.
The previous prime is 11001141003289. The next prime is 11001141003371. The reversal of 11001141003343 is 34330014110011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001141003343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001141001343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39597828 + ... + 39874681.
It is an arithmetic number, because the mean of its divisors is an integer number (2750305153570).
Almost surely, 211001141003343 is an apocalyptic number.
11001141003343 is a deficient number, since it is larger than the sum of its proper divisors (79610937).
11001141003343 is an equidigital number, since it uses as much as digits as its factorization.
11001141003343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79610936.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11001141003343 its reverse (34330014110011), we get a palindrome (45331155113354).
The spelling of 11001141003343 in words is "eleven trillion, one billion, one hundred forty-one million, three thousand, three hundred forty-three".
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