1100115543343 has 4 divisors (see below), whose sum is σ = 1126947629808. Its totient is φ = 1073283456880.

The previous prime is 1100115543341. The next prime is 1100115543361. The reversal of 1100115543343 is 3433455110011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100115543343 - 2¹ = 1100115543341 is a prime.

It is a super-2 number, since 2×1100115543343² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100115543341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13416043171 + ... + 13416043252.

It is an arithmetic number, because the mean of its divisors is an integer number (281736907452).

Almost surely, 2^{1100115543343} is an apocalyptic number.

1100115543343 is a deficient number, since it is larger than the sum of its proper divisors (26832086465).

1100115543343 is an equidigital number, since it uses as much as digits as its factorization.

1100115543343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26832086464.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 1100115543343 in words is "one trillion, one hundred billion, one hundred fifteen million, five hundred forty-three thousand, three hundred forty-three".