Base | Representation |
---|---|
bin | 1010000000010110101010… |
… | …1000101101011110111101 |
3 | 1102221201000120020100010112 |
4 | 2200011222220231132331 |
5 | 2420220424234131023 |
6 | 35221514234115405 |
7 | 2213544666450155 |
oct | 240055250553675 |
9 | 42851016210115 |
10 | 11001200302013 |
11 | 3561645851649 |
12 | 129813387bb65 |
13 | 61a540cc2b2c |
14 | 2a0664b43765 |
15 | 141276c54478 |
hex | a016aa2d7bd |
11001200302013 has 4 divisors (see below), whose sum is σ = 11017843570908. Its totient is φ = 10984557033120.
The previous prime is 11001200301977. The next prime is 11001200302049. The reversal of 11001200302013 is 31020300210011.
11001200302013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11001200301977) and next prime (11001200302049).
It can be written as a sum of positive squares in 2 ways, for example, as 5471281211929 + 5529919090084 = 2339077^2 + 2351578^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001200302013 - 214 = 11001200285629 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001200302063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8321633456 + ... + 8321634777.
It is an arithmetic number, because the mean of its divisors is an integer number (2754460892727).
Almost surely, 211001200302013 is an apocalyptic number.
It is an amenable number.
11001200302013 is a deficient number, since it is larger than the sum of its proper divisors (16643268895).
11001200302013 is an equidigital number, since it uses as much as digits as its factorization.
11001200302013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16643268894.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 11001200302013 its reverse (31020300210011), we get a palindrome (42021500512024).
The spelling of 11001200302013 in words is "eleven trillion, one billion, two hundred million, three hundred two thousand, thirteen".
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