11001212110111 has 4 divisors (see below), whose sum is σ = 11006360082352. Its totient is φ = 10996064137872.

The previous prime is 11001212110033. The next prime is 11001212110123. The reversal of 11001212110111 is 11101121210011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11001212110111 - 2¹⁵ = 11001212077343 is a prime.

It is a super-3 number, since 3×11001212110111³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001212110091 and 11001212110100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001272110111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2573982915 + ... + 2573987188.

It is an arithmetic number, because the mean of its divisors is an integer number (2751590020588).

Almost surely, 2^{11001212110111} is an apocalyptic number.

11001212110111 is a deficient number, since it is larger than the sum of its proper divisors (5147972241).

11001212110111 is an equidigital number, since it uses as much as digits as its factorization.

11001212110111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5147972240.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 11001212110111 its reverse (11101121210011), we get a palindrome (22102333320122).

The spelling of 11001212110111 in words is "eleven trillion, one billion, two hundred twelve million, one hundred ten thousand, one hundred eleven".