Base | Representation |
---|---|
bin | 10000000000100100011… |
… | …000011110000010000011 |
3 | 10220011121101200010110210 |
4 | 100000210120132002003 |
5 | 121011022214201034 |
6 | 2201220012525203 |
7 | 142324022616606 |
oct | 20004430360203 |
9 | 3804541603423 |
10 | 1100122022019 |
11 | 394617223a39 |
12 | 159264780803 |
13 | 7c98315c657 |
14 | 3b36378c33d |
15 | 1d93b5558e9 |
hex | 1002461e083 |
1100122022019 has 32 divisors (see below), whose sum is σ = 1495790150400. Its totient is φ = 719072956800.
The previous prime is 1100122022011. The next prime is 1100122022029. The reversal of 1100122022019 is 9102202210011.
It is not a de Polignac number, because 1100122022019 - 23 = 1100122022011 is a prime.
It is a super-2 number, since 2×11001220220192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100122021986 and 1100122022004.
It is not an unprimeable number, because it can be changed into a prime (1100122022011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 114246097 + ... + 114255725.
It is an arithmetic number, because the mean of its divisors is an integer number (46743442200).
Almost surely, 21100122022019 is an apocalyptic number.
1100122022019 is a deficient number, since it is larger than the sum of its proper divisors (395668128381).
1100122022019 is a wasteful number, since it uses less digits than its factorization.
1100122022019 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13155.
The product of its (nonzero) digits is 144, while the sum is 21.
The spelling of 1100122022019 in words is "one trillion, one hundred billion, one hundred twenty-two million, twenty-two thousand, nineteen".
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