11001221020021 has 4 divisors (see below), whose sum is σ = 11019344943232. Its totient is φ = 10983097096812.

The previous prime is 11001221020007. The next prime is 11001221020079. The reversal of 11001221020021 is 12002012210011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001221020021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001221019983 and 11001221020010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001221020081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9061960695 + ... + 9061961908.

It is an arithmetic number, because the mean of its divisors is an integer number (2754836235808).

Almost surely, 2^{11001221020021} is an apocalyptic number.

It is an amenable number.

11001221020021 is a deficient number, since it is larger than the sum of its proper divisors (18123923211).

11001221020021 is an equidigital number, since it uses as much as digits as its factorization.

11001221020021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18123923210.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 11001221020021 its reverse (12002012210011), we get a palindrome (23003233230032).

The spelling of 11001221020021 in words is "eleven trillion, one billion, two hundred twenty-one million, twenty thousand, twenty-one".