Base | Representation |
---|---|
bin | 1010000000010110110001… |
… | …1110010100001010100111 |
3 | 1102221201002201020121222002 |
4 | 2200011230132110022213 |
5 | 2420221010132200203 |
6 | 35221521254555515 |
7 | 2213545522501400 |
oct | 240055436241247 |
9 | 42851081217862 |
10 | 11001231131303 |
11 | 35616611990a6 |
12 | 1298142068b9b |
13 | 61a5474c840a |
14 | 2a0668c8a9a7 |
15 | 1412797e3d88 |
hex | a016c7942a7 |
11001231131303 has 6 divisors (see below), whose sum is σ = 12797350499736. Its totient is φ = 9429626683932.
The previous prime is 11001231131249. The next prime is 11001231131311. The reversal of 11001231131303 is 30313113210011.
It is not a de Polignac number, because 11001231131303 - 214 = 11001231114919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001231134303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 112257460475 + ... + 112257460572.
It is an arithmetic number, because the mean of its divisors is an integer number (2132891749956).
Almost surely, 211001231131303 is an apocalyptic number.
11001231131303 is a deficient number, since it is larger than the sum of its proper divisors (1796119368433).
11001231131303 is an equidigital number, since it uses as much as digits as its factorization.
11001231131303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 224514921061 (or 224514921054 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 11001231131303 its reverse (30313113210011), we get a palindrome (41314344341314).
The spelling of 11001231131303 in words is "eleven trillion, one billion, two hundred thirty-one million, one hundred thirty-one thousand, three hundred three".
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