110012330311133 has 4 divisors (see below), whose sum is σ = 110012391930588. Its totient is φ = 110012268691680.

The previous prime is 110012330311109. The next prime is 110012330311171. The reversal of 110012330311133 is 331113033210011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 96996556834489 + 13015773476644 = 9848683^2 + 3607738^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012330311133 - 2¹⁰ = 110012330310109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110012330311099 and 110012330311108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110012330611133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28049258 + ... + 31729883.

It is an arithmetic number, because the mean of its divisors is an integer number (27503097982647).

Almost surely, 2^{110012330311133} is an apocalyptic number.

It is an amenable number.

110012330311133 is a deficient number, since it is larger than the sum of its proper divisors (61619455).

110012330311133 is an equidigital number, since it uses as much as digits as its factorization.

110012330311133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61619454.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 110012330311133 its reverse (331113033210011), we get a palindrome (441125363521144).

The spelling of 110012330311133 in words is "one hundred ten trillion, twelve billion, three hundred thirty million, three hundred eleven thousand, one hundred thirty-three".