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110013012103231 = 195790158531749
BaseRepresentation
bin11001000000111001100110…
…100000011101000000111111
3112102112010210222010010002101
4121000321212200131000333
5103404423122044300411
61025551140254205531
732113114665543556
oct3100714640350077
9472463728103071
10110013012103231
1132065290331a16
12104093131b38a7
13495024b020123
141d2493013ad9d
15caba56c558c1
hex640e6681d03f

110013012103231 has 4 divisors (see below), whose sum is σ = 115803170635000. Its totient is φ = 104222853571464.

The previous prime is 110013012103229. The next prime is 110013012103249. The reversal of 110013012103231 is 132301210310011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110013012103231 - 21 = 110013012103229 is a prime.

It is a super-2 number, since 2×1100130121032312 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 5790158531749 = 110013012103231 / (1 + 1 + 0 + 0 + 1 + 3 + 0 + 1 + 2 + 1 + 0 + 3 + 2 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110013012103199 and 110013012103208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110013012104231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2895079265856 + ... + 2895079265893.

It is an arithmetic number, because the mean of its divisors is an integer number (28950792658750).

Almost surely, 2110013012103231 is an apocalyptic number.

110013012103231 is a deficient number, since it is larger than the sum of its proper divisors (5790158531769).

110013012103231 is an equidigital number, since it uses as much as digits as its factorization.

110013012103231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5790158531768.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 110013012103231 its reverse (132301210310011), we get a palindrome (242314222413242).

The spelling of 110013012103231 in words is "one hundred ten trillion, thirteen billion, twelve million, one hundred three thousand, two hundred thirty-one".

Divisors: 1 19 5790158531749 110013012103231