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110013102002122 = 2115000595545551
BaseRepresentation
bin11001000000111001101011…
…110111011000111111001010
3112102112011001020021110011221
4121000321223313120333022
5103404423313103031442
61025551153225112254
732113120136635504
oct3100715367307712
9472464036243157
10110013102002122
1132065327054320
121040933932868a
134950263838037
141d2493c05cd74
15caba5eab2467
hex640e6bdd8fca

110013102002122 has 8 divisors (see below), whose sum is σ = 180021439639872. Its totient is φ = 50005955455500.

The previous prime is 110013102002113. The next prime is 110013102002189. The reversal of 110013102002122 is 221200201310011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1100131020021222 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110013102002096 and 110013102002105.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2500297772754 + ... + 2500297772797.

It is an arithmetic number, because the mean of its divisors is an integer number (22502679954984).

Almost surely, 2110013102002122 is an apocalyptic number.

110013102002122 is a deficient number, since it is larger than the sum of its proper divisors (70008337637750).

110013102002122 is a wasteful number, since it uses less digits than its factorization.

110013102002122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5000595545564.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 110013102002122 its reverse (221200201310011), we get a palindrome (331213303312133).

The spelling of 110013102002122 in words is "one hundred ten trillion, thirteen billion, one hundred two million, two thousand, one hundred twenty-two".

Divisors: 1 2 11 22 5000595545551 10001191091102 55006551001061 110013102002122