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11001312031333 = 13846254771641
BaseRepresentation
bin1010000000010111000101…
…0010111011001001100101
31102221201022100110202221111
42200011301102323021211
52420221141340000313
635221533304545021
72213550524233501
oct240056122731145
942851270422844
1011001312031333
1135616a2924528
121298165182171
1361a55b1b2360
142a0675909301
1514128197443d
hexa01714bb265

11001312031333 has 4 divisors (see below), whose sum is σ = 11847566802988. Its totient is φ = 10155057259680.

The previous prime is 11001312031289. The next prime is 11001312031363. The reversal of 11001312031333 is 33313021310011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4541062974529 + 6460249056804 = 2130977^2 + 2541702^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001312031333 - 229 = 11000775160421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001312031363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 423127385808 + ... + 423127385833.

It is an arithmetic number, because the mean of its divisors is an integer number (2961891700747).

Almost surely, 211001312031333 is an apocalyptic number.

11001312031333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11001312031333 is a deficient number, since it is larger than the sum of its proper divisors (846254771655).

11001312031333 is an equidigital number, since it uses as much as digits as its factorization.

11001312031333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 846254771654.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 11001312031333 its reverse (33313021310011), we get a palindrome (44314333341344).

The spelling of 11001312031333 in words is "eleven trillion, one billion, three hundred twelve million, thirty-one thousand, three hundred thirty-three".

Divisors: 1 13 846254771641 11001312031333