110013231331332 has 72 divisors (see below), whose sum is σ = 317816977697856. Its totient is φ = 31432255274304.

The previous prime is 110013231331331. The next prime is 110013231331337. The reversal of 110013231331332 is 233133132310011.

110013231331332 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 1 + 3 + 2 + 313 + 313 + 32 = 666.

It is a super-2 number, since 2×110013231331332² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110013231331296 and 110013231331305.

It is not an unprimeable number, because it can be changed into a prime (110013231331331) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 139978938 + ... + 140762670.

It is an arithmetic number, because the mean of its divisors is an integer number (4414124690248).

Almost surely, 2^{110013231331332} is an apocalyptic number.

110013231331332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

110013231331332 is an abundant number, since it is smaller than the sum of its proper divisors (207803746366524).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110013231331332 is a wasteful number, since it uses less digits than its factorization.

110013231331332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1340777 (or 1340772 counting only the distinct ones).

The product of its (nonzero) digits is 2916, while the sum is 27.

Adding to 110013231331332 its reverse (233133132310011), we get a palindrome (343146363641343).

The spelling of 110013231331332 in words is "one hundred ten trillion, thirteen billion, two hundred thirty-one million, three hundred thirty-one thousand, three hundred thirty-two".