1100133213103 has 4 divisors (see below), whose sum is σ = 1100159599680. Its totient is φ = 1100106826528.

The previous prime is 1100133213097. The next prime is 1100133213139. The reversal of 1100133213103 is 3013123310011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100133213103 is a prime.

It is a super-3 number, since 3×1100133213103³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100133211103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13130650 + ... + 13214167.

It is an arithmetic number, because the mean of its divisors is an integer number (275039899920).

Almost surely, 2^{1100133213103} is an apocalyptic number.

1100133213103 is a deficient number, since it is larger than the sum of its proper divisors (26386577).

1100133213103 is an equidigital number, since it uses as much as digits as its factorization.

1100133213103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26386576.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100133213103 its reverse (3013123310011), we get a palindrome (4113256523114).

The spelling of 1100133213103 in words is "one trillion, one hundred billion, one hundred thirty-three million, two hundred thirteen thousand, one hundred three".