1100133234333 has 12 divisors (see below), whose sum is σ = 1816092958368. Its totient is φ = 628647562440.

The previous prime is 1100133234289. The next prime is 1100133234397. The reversal of 1100133234333 is 3334323310011.

1100133234333 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 1 + 3 + 323 + 4 + 333 = 666.

It is not a de Polignac number, because 1100133234333 - 2⁹ = 1100133233821 is a prime.

It is a super-3 number, since 3×1100133234333³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100133234297 and 1100133234306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100133234833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8731216083 + ... + 8731216208.

It is an arithmetic number, because the mean of its divisors is an integer number (151341079864).

Almost surely, 2^{1100133234333} is an apocalyptic number.

It is an amenable number.

1100133234333 is a deficient number, since it is larger than the sum of its proper divisors (715959724035).

1100133234333 is a wasteful number, since it uses less digits than its factorization.

1100133234333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17462432304 (or 17462432301 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 27.

Adding to 1100133234333 its reverse (3334323310011), we get a palindrome (4434456544344).

The spelling of 1100133234333 in words is "one trillion, one hundred billion, one hundred thirty-three million, two hundred thirty-four thousand, three hundred thirty-three".