11001425133 has 4 divisors (see below), whose sum is σ = 14668566848. Its totient is φ = 7334283420.

The previous prime is 11001425131. The next prime is 11001425137. The reversal of 11001425133 is 33152410011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11001425133 - 2¹ = 11001425131 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001425131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833570853 + ... + 1833570858.

It is an arithmetic number, because the mean of its divisors is an integer number (3667141712).

Almost surely, 2^11001425133 is an apocalyptic number.

It is an amenable number.

11001425133 is a deficient number, since it is larger than the sum of its proper divisors (3667141715).

11001425133 is an equidigital number, since it uses as much as digits as its factorization.

11001425133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3667141714.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 11001425133 its reverse (33152410011), we get a palindrome (44153835144).

The spelling of 11001425133 in words is "eleven billion, one million, four hundred twenty-five thousand, one hundred thirty-three".