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110014341 = 336671447
BaseRepresentation
bin1101000111010…
…10111110000101
321200000022022020
412203222332011
5211130424331
614525553353
72504051343
oct643527605
9250008266
10110014341
1157111448
1230a15859
1319a3ba58
141087a993
1599d1c96
hex68eaf85

110014341 has 4 divisors (see below), whose sum is σ = 146685792. Its totient is φ = 73342892.

The previous prime is 110014337. The next prime is 110014343. The reversal of 110014341 is 143410011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110014341 - 22 = 110014337 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110014341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110014343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18335721 + ... + 18335726.

It is an arithmetic number, because the mean of its divisors is an integer number (36671448).

Almost surely, 2110014341 is an apocalyptic number.

It is an amenable number.

110014341 is a deficient number, since it is larger than the sum of its proper divisors (36671451).

110014341 is an equidigital number, since it uses as much as digits as its factorization.

110014341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36671450.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 110014341 is about 10488.7721397693. The cubic root of 110014341 is about 479.1628071506.

Adding to 110014341 its reverse (143410011), we get a palindrome (253424352).

The spelling of 110014341 in words is "one hundred ten million, fourteen thousand, three hundred forty-one".

Divisors: 1 3 36671447 110014341