11001443211313 has 4 divisors (see below), whose sum is σ = 11005537536000. Its totient is φ = 10997348886628.

The previous prime is 11001443211301. The next prime is 11001443211377. The reversal of 11001443211313 is 31311234410011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11001443211313 - 2¹⁷ = 11001443080241 is a prime.

It is a super-3 number, since 3×11001443211313³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11001443221313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2047158313 + ... + 2047163686.

It is an arithmetic number, because the mean of its divisors is an integer number (2751384384000).

Almost surely, 2^{11001443211313} is an apocalyptic number.

It is an amenable number.

11001443211313 is a deficient number, since it is larger than the sum of its proper divisors (4094324687).

11001443211313 is an equidigital number, since it uses as much as digits as its factorization.

11001443211313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4094324686.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 11001443211313 its reverse (31311234410011), we get a palindrome (42312677621324).

The spelling of 11001443211313 in words is "eleven trillion, one billion, four hundred forty-three million, two hundred eleven thousand, three hundred thirteen".