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1100145551 = 7315070487
BaseRepresentation
bin100000110010010…
…1110001110001111
32211200010011222112
41001210232032033
54223114124201
6301055534235
736156040301
oct10144561617
92750104875
101100145551
115150046aa
1226852a37b
13146c01ccb
14a6179971
15668b40bb
hex4192e38f

1100145551 has 4 divisors (see below), whose sum is σ = 1115216112. Its totient is φ = 1085074992.

The previous prime is 1100145511. The next prime is 1100145589. The reversal of 1100145551 is 1555410011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1555410011 = 4573403523.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100145551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100145511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7535171 + ... + 7535316.

It is an arithmetic number, because the mean of its divisors is an integer number (278804028).

Almost surely, 21100145551 is an apocalyptic number.

1100145551 is a deficient number, since it is larger than the sum of its proper divisors (15070561).

1100145551 is an equidigital number, since it uses as much as digits as its factorization.

1100145551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15070560.

The product of its (nonzero) digits is 500, while the sum is 23.

The square root of 1100145551 is about 33168.4420948588. The cubic root of 1100145551 is about 1032.3256435705.

Adding to 1100145551 its reverse (1555410011), we get a palindrome (2655555562).

The spelling of 1100145551 in words is "one billion, one hundred million, one hundred forty-five thousand, five hundred fifty-one".

Divisors: 1 73 15070487 1100145551