1100199981 has 4 divisors (see below), whose sum is σ = 1466933312. Its totient is φ = 733466652.

The previous prime is 1100199973. The next prime is 1100199983. The reversal of 1100199981 is 1899910011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1899910011 = 3 ⋅633303337.

It is not a de Polignac number, because 1100199981 - 2³ = 1100199973 is a prime.

It is a super-2 number, since 2×1100199981² = 2420879996384800722, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100199983) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183366661 + ... + 183366666.

It is an arithmetic number, because the mean of its divisors is an integer number (366733328).

Almost surely, 2^1100199981 is an apocalyptic number.

It is an amenable number.

1100199981 is a deficient number, since it is larger than the sum of its proper divisors (366733331).

1100199981 is an equidigital number, since it uses as much as digits as its factorization.

1100199981 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 366733330.

The product of its (nonzero) digits is 5832, while the sum is 39.

The square root of 1100199981 is about 33169.2625935519. The cubic root of 1100199981 is about 1032.3426681536.

The spelling of 1100199981 in words is "one billion, one hundred million, one hundred ninety-nine thousand, nine hundred eighty-one".