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1100199998035 = 5770232856809
BaseRepresentation
bin10000000000101001000…
…001111011001001010011
310220011210211101201110101
4100000221001323021103
5121011202144414120
62201231440113231
7142325660453125
oct20005101731123
93804724351411
101100199998035
11394657242526
12159286905817
137c9963616c8
143b36dc89215
151d94330990a
hex1002907b253

1100199998035 has 8 divisors (see below), whose sum is σ = 1320257600640. Its totient is φ = 880148263104.

The previous prime is 1100199998003. The next prime is 1100199998039. The reversal of 1100199998035 is 5308999910011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100199998035 - 25 = 1100199998003 is a prime.

It is a super-2 number, since 2×11001999980352 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1100199998039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1043290 + ... + 1813519.

It is an arithmetic number, because the mean of its divisors is an integer number (165032200080).

Almost surely, 21100199998035 is an apocalyptic number.

1100199998035 is a deficient number, since it is larger than the sum of its proper divisors (220057602605).

1100199998035 is an equidigital number, since it uses as much as digits as its factorization.

1100199998035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2933837.

The product of its (nonzero) digits is 787320, while the sum is 55.

The spelling of 1100199998035 in words is "one trillion, one hundred billion, one hundred ninety-nine million, nine hundred ninety-eight thousand, thirty-five".

Divisors: 1 5 77023 385115 2856809 14284045 220039999607 1100199998035