1100199998003 has 2 divisors, whose sum is σ = 1100199998004. Its totient is φ = 1100199998002.

The previous prime is 1100199997999. The next prime is 1100199998039. The reversal of 1100199998003 is 3008999910011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100199998003 - 2² = 1100199997999 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100199998603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550099999001 + 550099999002.

It is an arithmetic number, because the mean of its divisors is an integer number (550099999002).

Almost surely, 2^{1100199998003} is an apocalyptic number.

1100199998003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100199998003 is an equidigital number, since it uses as much as digits as its factorization.

1100199998003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 50.

The spelling of 1100199998003 in words is "one trillion, one hundred billion, one hundred ninety-nine million, nine hundred ninety-eight thousand, three".