Base | Representation |
---|---|
bin | 10100011111100010… |
… | …10011010010010111 |
3 | 1001101202012112110022 |
4 | 22033301103102113 |
5 | 140013003004120 |
6 | 5015415015355 |
7 | 536432314211 |
oct | 121761232227 |
9 | 31352175408 |
10 | 11002000535 |
11 | 4736384929 |
12 | 217066a55b |
13 | 10644780b6 |
14 | 7652715b1 |
15 | 445d37025 |
hex | 28fc53497 |
11002000535 has 4 divisors (see below), whose sum is σ = 13202400648. Its totient is φ = 8801600424.
The previous prime is 11002000531. The next prime is 11002000543. The reversal of 11002000535 is 53500020011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11002000535 - 22 = 11002000531 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002000531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100200049 + ... + 1100200058.
It is an arithmetic number, because the mean of its divisors is an integer number (3300600162).
Almost surely, 211002000535 is an apocalyptic number.
11002000535 is a deficient number, since it is larger than the sum of its proper divisors (2200400113).
11002000535 is an equidigital number, since it uses as much as digits as its factorization.
11002000535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2200400112.
The product of its (nonzero) digits is 150, while the sum is 17.
Adding to 11002000535 its reverse (53500020011), we get a palindrome (64502020546).
The spelling of 11002000535 in words is "eleven billion, two million, five hundred thirty-five", and thus it is an aban number.
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