Base | Representation |
---|---|
bin | 11001000001000000001000… |
… | …010010000010110010110111 |
3 | 112102112210220102222020011220 |
4 | 121001000020102002302313 |
5 | 103410032000411431403 |
6 | 1025554255555401423 |
7 | 32113453455110265 |
oct | 3101001022026267 |
9 | 472483812866156 |
10 | 110020021202103 |
11 | 32068257830711 |
12 | 1040a74a5b3273 |
13 | 4950ac71906cc |
14 | 1d24dd6d85435 |
15 | cabd1726a953 |
hex | 641008482cb7 |
110020021202103 has 16 divisors (see below), whose sum is σ = 148726020439776. Its totient is φ = 72330664366080.
The previous prime is 110020021202083. The next prime is 110020021202141. The reversal of 110020021202103 is 301202120020011.
It is not a de Polignac number, because 110020021202103 - 216 = 110020021136567 is a prime.
It is a super-2 number, since 2×1100200212021032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110020021202803) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37713450 + ... + 40525847.
It is an arithmetic number, because the mean of its divisors is an integer number (9295376277486).
Almost surely, 2110020021202103 is an apocalyptic number.
110020021202103 is a deficient number, since it is larger than the sum of its proper divisors (38705999237673).
110020021202103 is an equidigital number, since it uses as much as digits as its factorization.
110020021202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78245794.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 110020021202103 its reverse (301202120020011), we get a palindrome (411222141222114).
The spelling of 110020021202103 in words is "one hundred ten trillion, twenty billion, twenty-one million, two hundred two thousand, one hundred three".
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