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110020123232002 = 255010061616001
BaseRepresentation
bin11001000001000000001110…
…010111010000011100000010
3112102112211011112221212220001
4121001000032113100130002
5103410032203021411002
61025554314042310214
732113456134255454
oct3101001627203402
9472484145855801
10110020123232002
11320682aa389245
121040a7787b836a
134950b12365129
141d250067442d4
15cabd211c1a87
hex64100e5d0702

110020123232002 has 4 divisors (see below), whose sum is σ = 165030184848006. Its totient is φ = 55010061616000.

The previous prime is 110020123231987. The next prime is 110020123232003. The reversal of 110020123232002 is 200232321020011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 90723510462321 + 19296612769681 = 9524889^2 + 4392791^2 .

It is not an unprimeable number, because it can be changed into a prime (110020123232003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505030807999 + ... + 27505030808002.

Almost surely, 2110020123232002 is an apocalyptic number.

110020123232002 is a deficient number, since it is larger than the sum of its proper divisors (55010061616004).

110020123232002 is an equidigital number, since it uses as much as digits as its factorization.

110020123232002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55010061616003.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 110020123232002 its reverse (200232321020011), we get a palindrome (310252444252013).

The spelling of 110020123232002 in words is "one hundred ten trillion, twenty billion, one hundred twenty-three million, two hundred thirty-two thousand, two".

Divisors: 1 2 55010061616001 110020123232002