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110020202111002 = 255010101055501
BaseRepresentation
bin11001000001000000010011…
…000100001010000000011010
3112102112211101001101100112111
4121001000103010022000122
5103410032333220023002
61025554325541102534
732113461112602421
oct3101002304120032
9472484331340474
10110020202111002
113206833a9641a7
121040a79b0b7a4a
134950b257c21b1
141d25012dd82b8
15cabd280a33d7
hex64101310a01a

110020202111002 has 4 divisors (see below), whose sum is σ = 165030303166506. Its totient is φ = 55010101055500.

The previous prime is 110020202110943. The next prime is 110020202111041. The reversal of 110020202111002 is 200111202020011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 107913265673161 + 2106936437841 = 10388131^2 + 1451529^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505050527749 + ... + 27505050527752.

Almost surely, 2110020202111002 is an apocalyptic number.

110020202111002 is a deficient number, since it is larger than the sum of its proper divisors (55010101055504).

110020202111002 is an equidigital number, since it uses as much as digits as its factorization.

110020202111002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55010101055503.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 110020202111002 its reverse (200111202020011), we get a palindrome (310131404131013).

Subtracting 110020202111002 from its reverse (200111202020011), we obtain a palindrome (90090999909009).

The spelling of 110020202111002 in words is "one hundred ten trillion, twenty billion, two hundred two million, one hundred eleven thousand, two".

Divisors: 1 2 55010101055501 110020202111002