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1100202211012 = 22275050552753
BaseRepresentation
bin10000000000101001001…
…010010111011011000100
310220011210222120011002111
4100000221022113123010
5121011203231223022
62201231555350404
7142326015331012
oct20005112273304
93804728504074
101100202211012
11394658514133
121592875b2404
137c996957a68
143b3702a38b2
151d9435e5477
hex100292976c4

1100202211012 has 6 divisors (see below), whose sum is σ = 1925353869278. Its totient is φ = 550101105504.

The previous prime is 1100202210971. The next prime is 1100202211037. The reversal of 1100202211012 is 2101122020011.

It can be written as a sum of positive squares in only one way, i.e., 1015995457156 + 84206753856 = 1007966^2 + 290184^2 .

It is a super-3 number, since 3×11002022110123 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100202210983 and 1100202211001.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 137525276373 + ... + 137525276380.

Almost surely, 21100202211012 is an apocalyptic number.

It is an amenable number.

1100202211012 is a deficient number, since it is larger than the sum of its proper divisors (825151658266).

1100202211012 is a wasteful number, since it uses less digits than its factorization.

1100202211012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 275050552757 (or 275050552755 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 1100202211012 its reverse (2101122020011), we get a palindrome (3201324231023).

The spelling of 1100202211012 in words is "one trillion, one hundred billion, two hundred two million, two hundred eleven thousand, twelve".

Divisors: 1 2 4 275050552753 550101105506 1100202211012