110021001102001 has 4 divisors (see below), whose sum is σ = 120022910293104. Its totient is φ = 100019091910900.

The previous prime is 110021001101969. The next prime is 110021001102053. The reversal of 110021001102001 is 100201100120011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110021001102001 - 2⁵ = 110021001101969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110021001102401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000954595535 + ... + 5000954595556.

It is an arithmetic number, because the mean of its divisors is an integer number (30005727573276).

Almost surely, 2^{110021001102001} is an apocalyptic number.

110021001102001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

110021001102001 is a deficient number, since it is larger than the sum of its proper divisors (10001909191103).

110021001102001 is a wasteful number, since it uses less digits than its factorization.

110021001102001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10001909191102.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 110021001102001 its reverse (100201100120011), we get a palindrome (210222101222012).

The spelling of 110021001102001 in words is "one hundred ten trillion, twenty-one billion, one million, one hundred two thousand, one".