Base | Representation |
---|---|
bin | 10000000000101001101… |
… | …000101010111100110011 |
3 | 10220011211112111202121221 |
4 | 100000221220222330303 |
5 | 121011212244432230 |
6 | 2201232441525511 |
7 | 142326143006155 |
oct | 20005150527463 |
9 | 3804745452557 |
10 | 1100210155315 |
11 | 394661a4a877 |
12 | 15928a1a3897 |
13 | 7c9984a9a2b |
14 | 3b371370ad5 |
15 | 1d94416427a |
hex | 10029a2af33 |
1100210155315 has 4 divisors (see below), whose sum is σ = 1320252186384. Its totient is φ = 880168124248.
The previous prime is 1100210155307. The next prime is 1100210155379. The reversal of 1100210155315 is 5135510120011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1100210155315 - 23 = 1100210155307 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1100210155315.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110021015527 + ... + 110021015536.
It is an arithmetic number, because the mean of its divisors is an integer number (330063046596).
Almost surely, 21100210155315 is an apocalyptic number.
1100210155315 is a deficient number, since it is larger than the sum of its proper divisors (220042031069).
1100210155315 is an equidigital number, since it uses as much as digits as its factorization.
1100210155315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 220042031068.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 1100210155315 its reverse (5135510120011), we get a palindrome (6235720275326).
The spelling of 1100210155315 in words is "one trillion, one hundred billion, two hundred ten million, one hundred fifty-five thousand, three hundred fifteen".
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