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1100212121111 = 5631954195597
BaseRepresentation
bin10000000000101001110…
…000001010111000010111
310220011211200012122012012
4100000221300022320113
5121011213300333421
62201232552014435
7142326165504305
oct20005160127027
93804750178165
101100212121111
113946630727a4
1215928a99141b
137c998a1771c
143b371723275
151d94440195b
hex10029c0ae17

1100212121111 has 4 divisors (see below), whose sum is σ = 1102166317272. Its totient is φ = 1098257924952.

The previous prime is 1100212121101. The next prime is 1100212121117. The reversal of 1100212121111 is 1111212120011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100212121111 - 226 = 1100145012247 is a prime.

It is a super-2 number, since 2×11002121211112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100212121117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 977097236 + ... + 977098361.

It is an arithmetic number, because the mean of its divisors is an integer number (275541579318).

Almost surely, 21100212121111 is an apocalyptic number.

1100212121111 is a deficient number, since it is larger than the sum of its proper divisors (1954196161).

1100212121111 is an equidigital number, since it uses as much as digits as its factorization.

1100212121111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1954196160.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 1100212121111 its reverse (1111212120011), we get a palindrome (2211424241122).

The spelling of 1100212121111 in words is "one trillion, one hundred billion, two hundred twelve million, one hundred twenty-one thousand, one hundred eleven".

Divisors: 1 563 1954195597 1100212121111