Base | Representation |
---|---|
bin | 10000000000101001110… |
… | …000011110001101101111 |
3 | 10220011211200100122211020 |
4 | 100000221300132031233 |
5 | 121011213310402203 |
6 | 2201232553425223 |
7 | 142326166254216 |
oct | 20005160361557 |
9 | 3804750318736 |
10 | 1100212200303 |
11 | 394663117247 |
12 | 15928aa0b213 |
13 | 7c998a44798 |
14 | 3b37174407d |
15 | 1d94441a153 |
hex | 10029c1e36f |
1100212200303 has 4 divisors (see below), whose sum is σ = 1466949600408. Its totient is φ = 733474800200.
The previous prime is 1100212200259. The next prime is 1100212200349. The reversal of 1100212200303 is 3030022120011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1100212200303 - 28 = 1100212200047 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100212201303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183368700048 + ... + 183368700053.
It is an arithmetic number, because the mean of its divisors is an integer number (366737400102).
Almost surely, 21100212200303 is an apocalyptic number.
1100212200303 is a deficient number, since it is larger than the sum of its proper divisors (366737400105).
1100212200303 is an equidigital number, since it uses as much as digits as its factorization.
1100212200303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 366737400104.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 1100212200303 its reverse (3030022120011), we get a palindrome (4130234320314).
The spelling of 1100212200303 in words is "one trillion, one hundred billion, two hundred twelve million, two hundred thousand, three hundred three".
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