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1100213101133 = 47919441118147
BaseRepresentation
bin10000000000101001110…
…011111010001001001101
310220011211202001102112022
4100000221303322021031
5121011214023214013
62201233025015525
7142326210025436
oct20005163721115
93804752042468
101100213101133
11394663682033
1215928b1845a5
137c998c9b813
143b3718da48d
151d944547008
hex10029cfa24d

1100213101133 has 8 divisors (see below), whose sum is σ = 1102576039680. Its totient is φ = 1097850438720.

The previous prime is 1100213101109. The next prime is 1100213101139. The reversal of 1100213101133 is 3311013120011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100213101133 - 210 = 1100213100109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100213101139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9253166 + ... + 9371312.

It is an arithmetic number, because the mean of its divisors is an integer number (137822004960).

Almost surely, 21100213101133 is an apocalyptic number.

It is an amenable number.

1100213101133 is a deficient number, since it is larger than the sum of its proper divisors (2362938547).

1100213101133 is a wasteful number, since it uses less digits than its factorization.

1100213101133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138067.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100213101133 its reverse (3311013120011), we get a palindrome (4411226221144).

The spelling of 1100213101133 in words is "one trillion, one hundred billion, two hundred thirteen million, one hundred one thousand, one hundred thirty-three".

Divisors: 1 479 19441 118147 9312239 56592413 2296895827 1100213101133