Base | Representation |
---|---|
bin | 110011001110111010… |
… | …0000001010000100101 |
3 | 101111222121111122220110 |
4 | 1212131310001100211 |
5 | 3300311042420312 |
6 | 122313205523233 |
7 | 10643305140426 |
oct | 1463564012045 |
9 | 344877448813 |
10 | 110021841957 |
11 | 42729509315 |
12 | 193a6113519 |
13 | a4b4ba6841 |
14 | 547a06b64d |
15 | 2cddeae43c |
hex | 199dd01425 |
110021841957 has 4 divisors (see below), whose sum is σ = 146695789280. Its totient is φ = 73347894636.
The previous prime is 110021841949. The next prime is 110021841991. The reversal of 110021841957 is 759148120011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 110021841957 - 23 = 110021841949 is a prime.
It is a super-2 number, since 2×1100218419572 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110021841257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18336973657 + ... + 18336973662.
It is an arithmetic number, because the mean of its divisors is an integer number (36673947320).
Almost surely, 2110021841957 is an apocalyptic number.
It is an amenable number.
110021841957 is a deficient number, since it is larger than the sum of its proper divisors (36673947323).
110021841957 is an equidigital number, since it uses as much as digits as its factorization.
110021841957 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36673947322.
The product of its (nonzero) digits is 20160, while the sum is 39.
Adding to 110021841957 its reverse (759148120011), we get a palindrome (869169961968).
The spelling of 110021841957 in words is "one hundred ten billion, twenty-one million, eight hundred forty-one thousand, nine hundred fifty-seven".
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