Base | Representation |
---|---|
bin | 10000000000101010010… |
… | …010011111111000010111 |
3 | 10220011212022010211101020 |
4 | 100000222102133320113 |
5 | 121011223101320043 |
6 | 2201233512532223 |
7 | 142326335134224 |
oct | 20005222377027 |
9 | 3804768124336 |
10 | 1100221120023 |
11 | 394668159813 |
12 | 1592919b1073 |
13 | 7c99a84871c |
14 | 3b3729c694b |
15 | 1d9450cce83 |
hex | 1002a49fe17 |
1100221120023 has 8 divisors (see below), whose sum is σ = 1487622923136. Its totient is φ = 723150031800.
The previous prime is 1100221119971. The next prime is 1100221120043. The reversal of 1100221120023 is 3200211220011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1100221120023 - 212 = 1100221115927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100221119984 and 1100221120011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100221120043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2582678473 + ... + 2582678898.
It is an arithmetic number, because the mean of its divisors is an integer number (185952865392).
Almost surely, 21100221120023 is an apocalyptic number.
1100221120023 is a deficient number, since it is larger than the sum of its proper divisors (387401803113).
1100221120023 is an equidigital number, since it uses as much as digits as its factorization.
1100221120023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5165357445.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 1100221120023 its reverse (3200211220011), we get a palindrome (4300432340034).
The spelling of 1100221120023 in words is "one trillion, one hundred billion, two hundred twenty-one million, one hundred twenty thousand, twenty-three".
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