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1100221120023 = 3715165357371
BaseRepresentation
bin10000000000101010010…
…010011111111000010111
310220011212022010211101020
4100000222102133320113
5121011223101320043
62201233512532223
7142326335134224
oct20005222377027
93804768124336
101100221120023
11394668159813
121592919b1073
137c99a84871c
143b3729c694b
151d9450cce83
hex1002a49fe17

1100221120023 has 8 divisors (see below), whose sum is σ = 1487622923136. Its totient is φ = 723150031800.

The previous prime is 1100221119971. The next prime is 1100221120043. The reversal of 1100221120023 is 3200211220011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1100221120023 - 212 = 1100221115927 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100221119984 and 1100221120011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100221120043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2582678473 + ... + 2582678898.

It is an arithmetic number, because the mean of its divisors is an integer number (185952865392).

Almost surely, 21100221120023 is an apocalyptic number.

1100221120023 is a deficient number, since it is larger than the sum of its proper divisors (387401803113).

1100221120023 is an equidigital number, since it uses as much as digits as its factorization.

1100221120023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5165357445.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1100221120023 its reverse (3200211220011), we get a palindrome (4300432340034).

The spelling of 1100221120023 in words is "one trillion, one hundred billion, two hundred twenty-one million, one hundred twenty thousand, twenty-three".

Divisors: 1 3 71 213 5165357371 15496072113 366740373341 1100221120023