Base | Representation |
---|---|
bin | 10100011111100100… |
… | …01110000110011001 |
3 | 1001101202122202220110 |
4 | 22033302032012121 |
5 | 140013033211213 |
6 | 5015424114533 |
7 | 536434336431 |
oct | 121762160631 |
9 | 31352582813 |
10 | 11002241433 |
11 | 4736529917 |
12 | 2170765a49 |
13 | 1064530941 |
14 | 7652d52c1 |
15 | 445d835c3 |
hex | 28fc8e199 |
11002241433 has 16 divisors (see below), whose sum is σ = 14984948160. Its totient is φ = 7177894464.
The previous prime is 11002241399. The next prime is 11002241491. The reversal of 11002241433 is 33414220011.
11002241433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11002241433 - 216 = 11002175897 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11002241333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27091 + ... + 150792.
It is an arithmetic number, because the mean of its divisors is an integer number (936559260).
Almost surely, 211002241433 is an apocalyptic number.
It is an amenable number.
11002241433 is a deficient number, since it is larger than the sum of its proper divisors (3982706727).
11002241433 is a wasteful number, since it uses less digits than its factorization.
11002241433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 178328.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 11002241433 its reverse (33414220011), we get a palindrome (44416461444).
The spelling of 11002241433 in words is "eleven billion, two million, two hundred forty-one thousand, four hundred thirty-three".
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