1100225131031 has 4 divisors (see below), whose sum is σ = 1184857833432. Its totient is φ = 1015592428632.

The previous prime is 1100225130997. The next prime is 1100225131039. The reversal of 1100225131031 is 1301315220011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100225131031 - 2¹⁰ = 1100225130007 is a prime.

It is a super-2 number, since 2×1100225131031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100225130994 and 1100225131012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100225131039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42316351181 + ... + 42316351206.

It is an arithmetic number, because the mean of its divisors is an integer number (296214458358).

Almost surely, 2^{1100225131031} is an apocalyptic number.

1100225131031 is a deficient number, since it is larger than the sum of its proper divisors (84632702401).

1100225131031 is an equidigital number, since it uses as much as digits as its factorization.

1100225131031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84632702400.

The product of its (nonzero) digits is 180, while the sum is 20.

The spelling of 1100225131031 in words is "one trillion, one hundred billion, two hundred twenty-five million, one hundred thirty-one thousand, thirty-one".