Base | Representation |
---|---|
bin | 10000000000101010110… |
… | …100011100111111111001 |
3 | 10220011212220220001101020 |
4 | 100000222310130333321 |
5 | 121011232341133423 |
6 | 2201234431413053 |
7 | 142326503606016 |
oct | 20005264347771 |
9 | 3804786801336 |
10 | 1100230021113 |
11 | 394672189293 |
12 | 159294984189 |
13 | 7c99c644042 |
14 | 3b373c6270d |
15 | 1d945c8a4e3 |
hex | 1002ad1cff9 |
1100230021113 has 8 divisors (see below), whose sum is σ = 1469240710848. Its totient is φ = 732353006064.
The previous prime is 1100230021091. The next prime is 1100230021211. The reversal of 1100230021113 is 3111200320011.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1100230021113 - 220 = 1100228972537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100230021092 and 1100230021101.
It is not an unprimeable number, because it can be changed into a prime (1100230021613) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 283416406 + ... + 283420287.
It is an arithmetic number, because the mean of its divisors is an integer number (183655088856).
Almost surely, 21100230021113 is an apocalyptic number.
It is an amenable number.
1100230021113 is a deficient number, since it is larger than the sum of its proper divisors (369010689735).
1100230021113 is an equidigital number, since it uses as much as digits as its factorization.
1100230021113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 566837343.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 1100230021113 its reverse (3111200320011), we get a palindrome (4211430341124).
The spelling of 1100230021113 in words is "one trillion, one hundred billion, two hundred thirty million, twenty-one thousand, one hundred thirteen".
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