Base | Representation |
---|---|
bin | 1010000000011010110000… |
… | …1101010111101100011101 |
3 | 1102221210212020022200120111 |
4 | 2200012230031113230131 |
5 | 2420230202402244013 |
6 | 35222215333450021 |
7 | 2213614155421534 |
oct | 240065415275435 |
9 | 42853766280514 |
10 | 11002300431133 |
11 | 356205a844970 |
12 | 12983a01a0911 |
13 | 61a687bba4cb |
14 | 2a072acb731b |
15 | 1412dd61373d |
hex | a01ac357b1d |
11002300431133 has 16 divisors (see below), whose sum is σ = 12109095777600. Its totient is φ = 9913274855680.
The previous prime is 11002300431019. The next prime is 11002300431149. The reversal of 11002300431133 is 33113400320011.
It is a cyclic number.
It is not a de Polignac number, because 11002300431133 - 213 = 11002300422941 is a prime.
It is a super-2 number, since 2×110023004311332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002300431163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47353038 + ... + 47584816.
It is an arithmetic number, because the mean of its divisors is an integer number (756818486100).
Almost surely, 211002300431133 is an apocalyptic number.
It is an amenable number.
11002300431133 is a deficient number, since it is larger than the sum of its proper divisors (1106795346467).
11002300431133 is a wasteful number, since it uses less digits than its factorization.
11002300431133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 270092.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11002300431133 its reverse (33113400320011), we get a palindrome (44115700751144).
The spelling of 11002300431133 in words is "eleven trillion, two billion, three hundred million, four hundred thirty-one thousand, one hundred thirty-three".
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