Base | Representation |
---|---|
bin | 10000000000101100010… |
… | …101101100001110011011 |
3 | 10220011221200212002112211 |
4 | 100000230111230032123 |
5 | 121011310402331301 |
6 | 2201241142015551 |
7 | 142330233352615 |
oct | 20005425541633 |
9 | 3804850762484 |
10 | 1100255511451 |
11 | 394685609588 |
12 | 1592a14175b7 |
13 | 7c9a49ca495 |
14 | 3b3773b9db5 |
15 | 1d948123051 |
hex | 1002c56c39b |
1100255511451 has 4 divisors (see below), whose sum is σ = 1123665203232. Its totient is φ = 1076845819672.
The previous prime is 1100255511431. The next prime is 1100255511479. The reversal of 1100255511451 is 1541155520011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1100255511451 - 229 = 1099718640539 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1100255511431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11704845820 + ... + 11704845913.
It is an arithmetic number, because the mean of its divisors is an integer number (280916300808).
Almost surely, 21100255511451 is an apocalyptic number.
1100255511451 is a deficient number, since it is larger than the sum of its proper divisors (23409691781).
1100255511451 is an equidigital number, since it uses as much as digits as its factorization.
1100255511451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23409691780.
The product of its (nonzero) digits is 5000, while the sum is 31.
The spelling of 1100255511451 in words is "one trillion, one hundred billion, two hundred fifty-five million, five hundred eleven thousand, four hundred fifty-one".
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