Base | Representation |
---|---|
bin | 1010000000011101011100… |
… | …0111100010100100110010 |
3 | 1102221212201101220222201202 |
4 | 2200013113013202210302 |
5 | 2420233141200314442 |
6 | 35222415011331202 |
7 | 2213641046412152 |
oct | 240072707424462 |
9 | 42855641828652 |
10 | 11003020323122 |
11 | 356239a140423 |
12 | 12985612b0b02 |
13 | 61a7710a2ab9 |
14 | 2a079874c762 |
15 | 141331914c32 |
hex | a01d71e2932 |
11003020323122 has 4 divisors (see below), whose sum is σ = 16504530484686. Its totient is φ = 5501510161560.
The previous prime is 11003020323101. The next prime is 11003020323131. The reversal of 11003020323122 is 22132302030011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10805414291281 + 197606031841 = 3287159^2 + 444529^2 .
It is a super-2 number, since 2×110030203231222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11003020323094 and 11003020323103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750755080779 + ... + 2750755080782.
Almost surely, 211003020323122 is an apocalyptic number.
11003020323122 is a deficient number, since it is larger than the sum of its proper divisors (5501510161564).
11003020323122 is an equidigital number, since it uses as much as digits as its factorization.
11003020323122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5501510161563.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 11003020323122 its reverse (22132302030011), we get a palindrome (33135322353133).
The spelling of 11003020323122 in words is "eleven trillion, three billion, twenty million, three hundred twenty-three thousand, one hundred twenty-two".
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