110031021223 has 4 divisors (see below), whose sum is σ = 111423819040. Its totient is φ = 108638223408.

The previous prime is 110031021197. The next prime is 110031021227. The reversal of 110031021223 is 322120130011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 322120130011 = 188443 ⋅1709377.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110031021223 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110031021197 and 110031021206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110031021227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 696398790 + ... + 696398947.

It is an arithmetic number, because the mean of its divisors is an integer number (27855954760).

Almost surely, 2^110031021223 is an apocalyptic number.

110031021223 is a deficient number, since it is larger than the sum of its proper divisors (1392797817).

110031021223 is an equidigital number, since it uses as much as digits as its factorization.

110031021223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1392797816.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 110031021223 its reverse (322120130011), we get a palindrome (432151151234).

The spelling of 110031021223 in words is "one hundred ten billion, thirty-one million, twenty-one thousand, two hundred twenty-three".