11003113113002 has 4 divisors (see below), whose sum is σ = 16504669669506. Its totient is φ = 5501556556500.

The previous prime is 11003113112977. The next prime is 11003113113007. The reversal of 11003113113002 is 20031131130011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10722553269961 + 280559843041 = 3274531^2 + 529679^2 .

It is not an unprimeable number, because it can be changed into a prime (11003113113007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750778278249 + ... + 2750778278252.

Almost surely, 2^{11003113113002} is an apocalyptic number.

11003113113002 is a deficient number, since it is larger than the sum of its proper divisors (5501556556504).

11003113113002 is an equidigital number, since it uses as much as digits as its factorization.

11003113113002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5501556556503.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11003113113002 its reverse (20031131130011), we get a palindrome (31034244243013).

The spelling of 11003113113002 in words is "eleven trillion, three billion, one hundred thirteen million, one hundred thirteen thousand, two".